Given a string and a non-empty substring sub, compute recursively the number of times that sub appears in the string, without the sub strings overlapping.
strCount("catcowcat", "cat") → 2
strCount("catcowcat", "cow") → 1
strCount("catcowcat", "dog") → 0
strCount("catcowcat", "cat") → 2
strCount("catcowcat", "cow") → 1
strCount("catcowcat", "dog") → 0
Expected
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Run
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strCount("catcowcat", "cat") → 2
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2
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OK
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strCount("catcowcat", "cow") → 1
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1
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OK
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strCount("catcowcat", "dog") → 0
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0
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OK
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strCount("cacatcowcat", "cat") → 2
|
2
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OK
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strCount("xyx", "x") → 2
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2
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OK
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strCount("iiiijj", "i") → 4
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4
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OK
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strCount("iiiijj", "ii") → 2
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2
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OK
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strCount("iiiijj", "iii") → 1
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1
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OK
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strCount("iiiijj", "j") → 2
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2
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OK
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strCount("iiiijj", "jj") → 1
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1
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OK
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strCount("aaabababab", "ab") → 4
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4
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OK
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strCount("aaabababab", "aa") → 1
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1
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OK
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strCount("aaabababab", "a") → 6
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6
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OK
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strCount("aaabababab", "b") → 4
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4
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OK
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other tests
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OK
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public int strCount(String str, String sub) {
int index = str.indexOf(sub);
if (index < 0)
return 0;
return 1 + strCount(str.substring(index + sub.length()), sub);
}
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